Class- 5 COMPUTER LESSON-5 INTRODUCTION TO MS EXCEL 2013

 EVENTS CONVENT HIGH SCHOOL

12/01/2021                    CLASS-5                                 SLOT-2

COMPUTER

LESSON -5 INTRODUCTION TO MS EXCEL 2013

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D.Answer the following questions:-

Que-1 What is a spreadsheet?

Ans-1  Spreadsheet is a system of recording numerical data consisting of a grid( or table) of rows, columns and cells, where data is entered.

 

Que-2 Write down the features of MS Excel?

Ans-2 The features of MS Excel are

(a)    Arrange data in an organized way.

(b)   Type less and get more.

(c)    Perform calculations

(d)   Auto recalculations

(e)    Auto format table.

 

Que-3 Explain the various components of MS Excel windows?

Ans-3 Various components of MS Excel Windows are :

(a)    Title bar

(b)   Quick access toolbar

(c)    Ribbon

(d)   File tab

(e)    Formula bar

(f)    Sheet tab

(g)   Status bar

 

Que-4 Write a short note on cell?

Ans-4 A cell is the space which is formed by the intersection of one eow and one column. Each small rectangle in a spreadsheet is called a cell.

 

Que-5 Write the steps to save a worksheet?
Ans-5 To saving worksheet.

Step-1 Click on file tab.

Step -2 select the save/save as option the file will be saved.

Stept-3 click on save icon on the quick access toolbar.

 

 

 

 

CLASS-7 MATHS CHAPTER-4 SIMPLE EQUATIONS

 

EVENTS CONVENT HIGH SCHOOL

12/01/2021                        CLASS-7                                  SLOT-2

MATHS

Chapter-4 SIMPLE EQUATIONS

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Question 1:Complete the last column of the table.

S. No.	Equation	Value	Say, whether the equation is satisfied. (Yes/No)
(i)	x + 3 = 0	x = 3	–
(ii)	x + 3 = 0	x = 0	–
(iii)	x + 3 = 0	x = − 3	–
(iv)	x − 7 = 1	x = 7	–
(v)	x − 7 = 1	x = 8	–
(vi)	5x = 25	x = 0	–
(vii)	5x = 25	x = 5	–
(viii)	5x = 25	x = − 5	–
(ix)		m = − 6	–
(x)		m = 0	–
(xi)		m = 6	–

Answer:

(i) x + 3 = 0

L.H.S. = x + 3

By putting x = 3,

L.H.S. = 3 + 3 = 6 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ii) x + 3 = 0

L.H.S. = x + 3

By putting x = 0,

L.H.S. = 0 + 3 = 3 ≠ R.H.S.

∴ No, the equation is not satisfied.

(iii) x + 3 = 0

L.H.S. = x + 3

By putting x = −3,

L.H.S. = − 3 + 3 = 0 = R.H.S.

∴ Yes, the equation is satisfied.

(iv) x − 7 = 1

L.H.S. = x − 7

By putting x = 7,

L.H.S. = 7 − 7 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(v) x − 7 = 1

L.H.S. = x − 7

By putting x = 8,

L.H.S. = 8 − 7 = 1 = R.H.S.

∴ Yes, the equation is satisfied.

(vi) 5x = 25

L.H.S. = 5x

By putting x = 0,

L.H.S. = 5 × 0 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(vii) 5x = 25

L.H.S. = 5x

By putting x = 5,

L.H.S. = 5 × 5 = 25 = R.H.S.

∴ Yes, the equation is satisfied.

(viii) 5x = 25

L.H.S. = 5x

By putting x = −5,

L.H.S. = 5 × (−5) = −25 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ix)  = 2

L.H.S. = 

By putting m = −6,

L. H. S. =   ≠ R.H.S.

∴No, the equation is not satisfied.

(x)  = 2

L.H.S. = 

By putting m = 0,

L.H.S. =   ≠ R.H.S.

∴No, the equation is not satisfied.

(xi)  = 2

L.H.S. = 

By putting m = 6,

L.H.S. =   = R.H.S.

∴ Yes, the equation is satisfied.

Question 2:Check whether the value given in the brackets is a solution to the given equation or not:

(a) n + 5 = 19 (n = 1)       (b) 7n + 5 = 19 (n = − 2)

(c) 7n + 5 = 19 (n = 2)     (d) 4p − 3 = 13 (p = 1)

 

Answer:(a) n + 5 = 19 (n = 1)

Putting n = 1 in L.H.S.,

n + 5 = 1 + 5 = 6 ≠ 19

As L.H.S. ≠ R.H.S.,

Therefore, n = 1 is not a solution of the given equation, n + 5 = 19.

 

(b) 7n + 5 = 19 (n = −2)

Putting n = −2 in L.H.S.,

7n + 5 = 7 × (−2) + 5 = −14 + 5 = −9 ≠ 19

As L.H.S. ≠ R.H.S.,

Therefore, n = −2 is not a solution of the given equation, 7n + 5 = 19.

 

(c) 7n + 5 = 19 (n = 2)

Putting n = 2 in L.H.S.,

7n + 5 = 7 × (2) + 5 = 14 + 5 = 19 = R.H.S.

As L.H.S. = R.H.S.,

Therefore, n = 2 is a solution of the given equation, 7n + 5 = 19.

 

(d) 4p − 3 = 13 (p = 1)

Putting p = 1 in L.H.S.,

4p − 3 = (4 × 1) − 3 = 1 ≠ 13

As L.H.S ≠ R.H.S.,

Therefore, p = 1 is not a solution of the given equation, 4p − 3 = 13.

 

Question 3:Solve the following equations by trial and error method:

(i) 5p + 2 = 17

 

Answer:

(i) 5p + 2 = 17

Putting p = 1 in L.H.S.,

(5 × 1) + 2 = 7 ≠ R.H.S.

Putting p = 2 in L.H.S.,

(5 × 2) + 2 = 10 + 2 = 12 ≠ R.H.S.

Putting p = 3 in L.H.S.,

(5 × 3) + 2 = 17 = R.H.S.

Hence, p = 3 is a solution of the given equation.

 

Question 4:Write equations for the following statements:

(i) The sum of numbers x and 4 is 9.

(ii) 2 subtracted from y is 8.

(iii) Ten times a is 70.

 Answer:(i) x + 4 = 9

(ii) y − 2 = 8

(iii) 10a = 70

Question 5:Write the following equations in statement forms:

 (i) m − 7 = 3         (ii) 2m = 7   

 Answer: (i) 7 subtracted from m is 3.       (ii) Twice of a number m is 7.